47. The function space \(H(\operatorname{div})\)#
\(\DeclareMathOperator{\opdiv}{div}\) We will
give a clear definition of the space \(H(\operatorname{div})\)
understand its boundary values, i.e. its trace
understand its continuity properties
As for the Sobolev space \(H^1\), we need a weak definition of the differential operator \(\operatorname{div}\). We call
the weak divergence iff
holds for all smooth testfunctions with compact support \(\varphi \in C_0^\infty(\Omega)\).
We define the function space
equipped with the norm
Smooth functions are dense in \(H(\operatorname{div})\), i.e. \(\forall \, \sigma \in H(\operatorname{div})\) and \(\forall \varepsilon > 0\) there exists \(\sigma^\varepsilon \in C^\infty\) such that
(proven by commuting mollifiers).
For smooth functions \(\sigma\) and \(\varphi\) there holds the integration by parts formula
47.1. Normal-trace of functions in \(H(\operatorname{div})\)#
From the integration by parts formula applied to smooth functions \(\sigma\) we get
and thus
We have shown that
Now we use density of smooth functions in \(H(\operatorname{div})\) to uniquely extend the trace operator \(\operatorname{tr}_n\) to the whole space \(H(\operatorname{div})\).
Having well-defined normal boundary values, we get now the integration by parts formula for arbitrary functions \(\sigma \in H(\operatorname{div})\).
Exercise: Prove that for all \(\sigma_n \in H^{-1/2}(\partial \Omega)\) there exists a \(\sigma \in H(\operatorname{div})\) such that \(\operatorname{tr}_n \sigma = \sigma_n\).
47.2. \(H(\operatorname{div})\) on sub-domains#
Assume that we have a non-overlapping domain decomposition
with interfaces
Theorem: for \(\sigma \in [L_2(\Omega)]^n\) such that
\(\sigma_{|\Omega_i} \in H(\operatorname{div}, \Omega_i)\) with \(d_i = \operatorname{div}_{\Omega_i} \sigma_{|\Omega_i}\)
\(\sigma_{\Omega_i} n_i = - \sigma_{\Omega_j} n_j\) on \(\gamma_{ij}\)
then there is \(\sigma \in H(\operatorname{div}, \Omega)\) with
\[ (\operatorname{div} \sigma)_{|\Omega_i} = d_i \]
Proof: We apply the integration by parts formula on sub-domains, and observe that boundary terms cancel out: